Combined circadian model
[Generated automatically as a Tutorial summary]
Model Description
- Name:
circ_combined
- Title:
Combined circadian model
- Author:
PoPy for PK/PD
- Abstract:
A PD Model based on the concentration of drug in the plasma.
The PD model uses three sine functions with different amplitudes and frequencies, which simulates a circadian rhythm for the generation of a biomarker.
The amount in the central compartment is determined by CL, V1, Q and V2, PK parameters, which have been previously estimated for each individual in the data file.
The amount in the central compartment influences the rate of production of a biomarker.
- Keywords:
PD; Pharmacodynamics; sine function; Circadian rhythm
- Input Script:
- Diagram:
Comparison
True objective value
1072.0713
Final fitted objective value
1638.2986
Compare Main f[X]
Name |
Initial |
Fitted |
True |
Abs. Error |
Prop. Error |
|---|---|---|---|---|---|
f[AMP1] |
3 |
2.54 |
1.2 |
1.34e+00 |
111.90% |
f[INT1] |
5 |
15.4 |
3.5 |
1.19e+01 |
339.69% |
f[AMP2] |
3 |
0.691 |
2.5 |
1.81e+00 |
72.37% |
f[INT2] |
5 |
0.1 |
6 |
5.90e+00 |
98.33% |
f[AMP3] |
3 |
3.13 |
3.2 |
6.90e-02 |
2.16% |
f[INT3] |
5 |
60.8 |
13 |
4.78e+01 |
367.87% |
f[KOUT] |
0.1 |
0.0478 |
0.05 |
2.19e-03 |
4.39% |
Compare Noise f[X]
Name |
Initial |
Fitted |
True |
Abs. Error |
Prop. Error |
|---|---|---|---|---|---|
f[ANOISE] |
10 |
14.6 |
5 |
9.62e+00 |
192.49% |
Compare Variance f[X]
No Variance f[X] values to compare.
Outputs
Fitted f[X] values (after fitting)
f[AMP1] = 2.5428
f[INT1] = 15.3892
f[AMP2] = 0.6906
f[INT2] = 0.1000
f[AMP3] = 3.1310
f[INT3] = 60.8236
f[KOUT] = 0.0478
f[ANOISE] = 14.6244
Generated data .csv file
- Synthetic Data:
Gen and Fit Summaries
Gen: Combined circadian model (gen)
Fit: Combined circadian model (fit)
Inputs
True f[X] values (for simulation)
f[AMP1] = 1.2000
f[INT1] = 3.5000
f[AMP2] = 2.5000
f[INT2] = 6.0000
f[AMP3] = 3.2000
f[INT3] = 13.0000
f[KOUT] = 0.0500
f[ANOISE] = 5.0000
Starting f[X] values (before fitting)
f[AMP1] = 3.0000
f[INT1] = 5.0000
f[AMP2] = 3.0000
f[INT2] = 5.0000
f[AMP3] = 3.0000
f[INT3] = 5.0000
f[KOUT] = 0.1000
f[ANOISE] = 10.0000